The simplest kind of **linked list** is a **singly-linked list **, which has one link per node. This link points to the next node in the list, or to a null value or empty list if it is the final node.A singly linked list’s node is divided into two parts. The first part holds or points to information about the node, and second part holds the address of next node. A singly linked list travels one way.

/* A simple implementation of linked list in C plus plus (CPP/C++) */ /* Program downloaded from www.GeeksPlanet.net For any help, post comment here http://geeksplanet.net/2008/11/data-structures/implementation-of-singly-linked-list-using-c-plus-plus/ Compiler used: g++ */ #include<iostream> using namespace std; struct node{ int data; node *next; }; /* This function adds a node at the end of the list and returns pointer to the added node, This takes pointer to the first node and pointer to the last node as argument. By giving the last node as argument we are saving some computer labour as it need not travel from the start to the end to find the last node */ node * addnode(node*,node*); /* This function just takes the first node as the argument and traverses the entire list displaying the data in each node. */ void shownodes(node*); /* This function takes the first node as argument and traverses the list until it finds the last node and deletes it and returns pointer to the new last node. */ node * delete_node(node*); /* *f and *l are the global variables keeping track of first and last nodes. */ node *f,*l; main() { int i,ch; f=l=NULL; cout<<"\t 1 to add a node"<<endl; cout<<"\t 2 to see the nodes"<<endl; cout<<"\t 3 to delete a node"<<endl; cout<<"\t 0 to exit"<<endl; while(1) { cout<<"Enter your choice:"; cin>>ch; switch(ch) { case 1: { if(f==NULL) l=f=addnode(f,l); //Since first node is the last node else l=addnode(f,l); //Last node is the new node added break; } case 2: shownodes(f);break; case 3: l=delete_node(f);break; // Last node has been changed to the last but one. case 0: break; default: cout<<"Please enter a proper choice"<<endl;break; } if(ch==0) break; } } node * addnode(node *f,node *l) { node *n; n=new node; //Allocating memory for the new node cout<<"Enter data:"; cin>>n->data; //This is going to be the last node, so its next point to NULL n->next=NULL; //If there is no first node, then the new node is the first and last node. if(f==NULL) {f=l=n;return f;} else { // Pointing the last node to the new node l->next=n; //Setting the new node as the last node l=n;return l; } } void shownodes(node *f) { cout<<"showing data"<<endl; node *guest=f; while(guest!=NULL) { cout<<"\t"<<guest->data<<endl; guest=guest->next; } } node * delete_node(node *f) { node *guest,*lb; guest=lb=f; while(guest->next!=NULL) { lb=guest; guest=guest->next; } lb->next=NULL; cout<<"node deleted"<<endl; return lb; }

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[…] Most of the times most of the array is left unused. A better way to implement stack is by using a linked list. By using a single linked list to implement a stack there is no wastage of space. Implementation of […]

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